2(3r+2)=-[1+(2-r)]

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Solution for 2(3r+2)=-[1+(2-r)] equation:


Simplifying
2(3r + 2) = -1[1 + (2 + -1r)]

Reorder the terms:
2(2 + 3r) = -1[1 + (2 + -1r)]
(2 * 2 + 3r * 2) = -1[1 + (2 + -1r)]
(4 + 6r) = -1[1 + (2 + -1r)]

Remove parenthesis around (2 + -1r)
4 + 6r = -1[1 + 2 + -1r]

Combine like terms: 1 + 2 = 3
4 + 6r = -1[3 + -1r]
4 + 6r = [3 * -1 + -1r * -1]
4 + 6r = [-3 + 1r]

Solving
4 + 6r = -3 + 1r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-1r' to each side of the equation.
4 + 6r + -1r = -3 + 1r + -1r

Combine like terms: 6r + -1r = 5r
4 + 5r = -3 + 1r + -1r

Combine like terms: 1r + -1r = 0
4 + 5r = -3 + 0
4 + 5r = -3

Add '-4' to each side of the equation.
4 + -4 + 5r = -3 + -4

Combine like terms: 4 + -4 = 0
0 + 5r = -3 + -4
5r = -3 + -4

Combine like terms: -3 + -4 = -7
5r = -7

Divide each side by '5'.
r = -1.4

Simplifying
r = -1.4

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